#### Answer

21.4L

#### Work Step by Step

The formula for glucose is:
C$_6$H$_12$O$_6$ + 6O$_2$ --> 6CO$_2$ + 6H$_2$O
We are given 24.5g of glucose at
T = 37 Celsius = 310 Kelvin
P = 0.970 atm
And we want to find the volume of CO$_2$ produced when 24.5 of glucose is consumed.
We know from the formula that for 1 mole of glucose consumed, 6 moles of CO$_2$ are produced so the ratio is;
1 mole glucose : 6 mole CO$_2$
24.5 g glucose x (1 mol glucose/180g glucose) = 0.136 mole
1 mole glucose : 6 mole CO$_2$ = 0.136 mole glucose : x mole CO$_2$
By using simple algebra, we get x = 0.816 mole CO$_2$ produced
Now to find the volume of this amount of CO$_2$ using the combined gas law,
V = nRT/P
V = (0.816 mol x 0.08201 x 310)/(0.970) = 21.4L