Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 10 - Gases - Exercises - Page 432: 10.2b

Answer

$V_{2}= 1/2V_{1}$

Work Step by Step

$P_{1}V_{1}=P_{2}V_{2}$ (Boyle's Law) 1 atm $\times V_{1}$ = 2 atm $\times V_{2}$
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