Chemistry: Principles and Practice (3rd Edition)

Published by Cengage Learning
ISBN 10: 0534420125
ISBN 13: 978-0-53442-012-3

Chapter 21 - Nuclear Chemistry - Questions and Exercises - Exercises - Page 934: 21.39


17.0 days.

Work Step by Step

$\ln (\frac{N}{N_{0}})=-\frac{0.693}{t_{1/2}}t$ $\implies t_{1/2}=-\frac{0.693}{\ln (\frac{N}{N_{0}})}t=-\frac{0.693}{\ln(\frac{650}{865})}\times7.00\,days=17.0\,days$
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