Chapter 2 - Atoms, Molecules, and Ions - Questions and Exercises - Exercises - Page 83: 2.34

a) 16 protons, 16 neutrons. b) 12 protons, 12 neutrons. c) 17 protons, 20 neutrons.

a) In this case, Z=16, A=32. Number of protons = Z = 16 Number of neutrons (n) = A-Z = 32-16 = 16 b) Mass number, A = 24 Atomic number, Z= 12 = Number of protons. n= A-Z = 24-12 = 12 c) From the symbol, we find that Z = 17 and A = 37. Number of protons = Z =17. Number of neutrons, n = A-Z = 37-17 = 20