Chapter 2 - Atoms, Molecules, and Ions - Questions and Exercises - Exercises - Page 83: 2.33

a) 33 protons, 46 neutrons. b) 23 protons, 28 neutrons. c) 52 protons, 76 neutrons.

a) In this case, A = 79 and Z= 33. Number of protons = Z = 33. Number of neutrons (n) = A-Z = 79-33 = 46 b) Here, Z=23, A=51. Number of protons = Z = 23 n = A-Z = 51-23 = 28 c) A= 128, Z = 52 (Obtained from the symbol) Number of protons = Z = 52 n= A-Z = 128-52 = 76