# Chapter 5 - Electron Configurations and the Periodic Table - Questions for Review and Thought - Topical Questions - Page 240b,: 55

The ion is $Fe^{2+}$. Its ground state configuration is $[Ar]4s^{2}3d^{6}$. 4s electrons are at a higher energy level. Iron loses two 4s electrons to form the $Fe^{2+}$ ion. The $V^{2+}$ ion will have three 3d electrons, as it loses its two 4s electrons to form the $V^{2+}$ ion.

#### Work Step by Step

See the periodic table

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