Chemistry: The Molecular Science (5th Edition)

Published by Cengage Learning
ISBN 10: 1285199049
ISBN 13: 978-1-28519-904-7

Chapter 4 - Energy and Chemical Reactions - Problem Solving Practice 4.7 - Page 171: b


Heat transfer : -0.841kJ or -841J.

Work Step by Step

Molar Mass ($I_2$): 126.9* 2 = 253.8g/mol 1. Calculate the amount in moles: $3.42g \times \frac{1 mol (I_2)}{ 253.8} = 0.0135 mol$ 2. Divide the amount by the coefficient of $I_2$: $\frac{0.0135}{ 1} = 0.0135 mol - reaction$ 3. Find the necessary heat: ** Since we are talking about the reverse reaction, the $\Delta_rH^{\circ}$ is negative. $0.0135mol-reaction \times (-62.4) kJ/mol-reaction = (-0.841)kJ$
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