Answer
The heat transfer is 2.46 kJ.
Work Step by Step
Molar Mass ($I_2$):
126.9* 2 = 253.8g/mol
1. Calculate the amount in moles:
$10.0g \times \frac{1 mol (I_2)}{ 253.8} = 0.03094 mol$
2. Divide the amount by the coefficient of $I_2$:
$\frac{0.03094}{ 1} = 0.03094 mol - reaction$
3. Find the necessary heat:
$0.03094mol-reaction \times 62.4 kJ/mol-reaction = 2.46 kJ$
