## Chemistry: The Molecular Science (5th Edition)

Molar Mass ($I_2$): 126.9* 2 = 253.8g/mol 1. Calculate the amount in moles: $10.0g \times \frac{1 mol (I_2)}{ 253.8} = 0.03094 mol$ 2. Divide the amount by the coefficient of $I_2$: $\frac{0.03094}{ 1} = 0.03094 mol - reaction$ 3. Find the necessary heat: $0.03094mol-reaction \times 62.4 kJ/mol-reaction = 2.46 kJ$