## Chemistry: The Molecular Science (5th Edition)

$C(graphite) + \frac{1}{2}O_2(g) -- \gt CO(g)$ $\Delta_fH^{\circ}\{CO\} = -110.525kJ/mol$
1. Write the separated atoms, and their coefficients, to form a single $CO$ $1C + 1O -- \gt CO$ 2. Analyze appendix J, and find the standard state for carbon and hydrogen. - Divide the coefficient by the number of atoms in each compound in standard state: $\frac{1}{1} C(graphite) + \frac{1}{2}O_2(g) -- \gt CO(g)$ Just add the $\Delta_fH^{\circ}$ after the reaction. $C(graphite) + \frac{1}{2}O_2(g) -- \gt CO(g)$; $\Delta_fH^{\circ}\{CO\} = -110.525kJ/mol$