Chemistry: The Molecular Science (5th Edition)

Published by Cengage Learning
ISBN 10: 1285199049
ISBN 13: 978-1-28519-904-7

Chapter 4 - Energy and Chemical Reactions - Problem Solving Practice 4.12 - Page 181: a


$\frac{1}{2} N_2(g) + \frac{3}{2}H_2(g) -- \gt NH_3(g)$; $\Delta_fH^{\circ}\{NH_3\} = -46.11kJ/mol$

Work Step by Step

1. Write the separated atoms, and their coefficients, to form a single $NH_3$ $N + 3H -- \gt NH_3(g)$ 2. Analyze the appendix J, and find the standart state for nitrogen and hydrogen. - Divide the coefficient by the number of atoms in each compound in standard state: $\frac{1}{2} N_2(g) + \frac{3}{2}H_2(g) -- \gt NH_3(g)$ Just add the $\Delta_fH^{\circ}$ after the reaction. $\frac{1}{2} N_2(g) + \frac{3}{2}H_2(g) -- \gt NH_3(g)$; $\Delta_fH^{\circ}\{NH_3\} = -46.11kJ/mol$
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