Chemistry: The Molecular Science (5th Edition)

Published by Cengage Learning
ISBN 10: 1285199049
ISBN 13: 978-1-28519-904-7

Chapter 3 - Chemical Reactions - Questions for Review and Thought - Topical Questions - Page 148f: 83b


$[K^+] = 0.0318M$ $[Cr_2O{_7}^{2-}] = 0.0159M$

Work Step by Step

As we calculated in the last exercise, the molarity of $K_2Cr_2O_7$ is equal to $0.0159M. $ There are 2 $K^+$ in each $K_2Cr_2O_7$, so: $[K^+]=2 \times 0.0159M=0.0318M$ There is 1 $Cr_2O{_7}^{2-}$ in each $K_2Cr_2O_7$, so: $[Cr_2O{_7}^{2-}]=1 \times 0.0159M=0.0159M$
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