## Chemistry: The Molecular Science (5th Edition)

Published by Cengage Learning

# Chapter 3 - Chemical Reactions - Questions for Review and Thought - Topical Questions - Page 148f: 82b

#### Answer

$[Na^+] = 0.508M$ $[CO{_3}^{2-}] = 0.254M$

#### Work Step by Step

As we calculated in the last exercise, the molarity of $Na_2CO_3$ is equal to 0.254M. There are 2 $Na^+$ in each $Na_2CO_3$, so: $[Na^+] = 2 \times 0.254M = 0.508M$ There is 1 $C{O_3}^{2-}$ in each $Na_2CO_3$, so: $[C{O_3}^{2-}] = 1 \times 0.254M = 0.254M$

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.