Answer
- This is a gas formation reaction.
Products:
$2KClO_4$
$CO_2$ and $H_2O$
Completed equation:
$K_2CO_3(aq) + 2HClO_4(aq) \lt -- \gt 2KClO_4(aq) + CO_2(g) + H_2O(l)$
Work Step by Step
1. Write and analyze the products of the reaction:
- Since we have 2 ionic compounds, we will have a double displacement reaction. So, the products are:
$KClO_4$: Which is soluble in water*
$H_2CO_3$: Which is soluble in water*
* According to table 3.1 (Page 101).
Since we have an insoluble product, there will be precipitation.
- But, the carbonic acid $(H_2CO_3)$, turns to $CO_2(g)$ and $H_2O(l)$.
- Therefore, this is a gas formation reaction.
Since we already have the reactants and the products, the chemical reaction is:
$K_2CO_3(aq) + HClO_4(aq) \lt -- \gt KClO_4(aq) + CO_2(g) + H_2O(l)$
- Balancing the reaction:
$K_2CO_3(aq) + 2HClO_4(aq) \lt -- \gt 2KClO_4(aq) + CO_2(g) + H_2O(l)$
