- This is a precipitation reaction. Products: $ZnCO_3$ $2NaCl$ Completed equation: $ZnCl_2(aq) + Na_2CO_3(aq) \lt -- \gt ZnCO_3(s) + 2NaCl(aq)$
Work Step by Step
1. Write and analyze the products of the reaction: - Since we have 2 ionic compounds, we will have a double displacement reaction. So, the products are: $ZnCO_3$: Which is insoluble in water* $Na_2Cl_2 --> 2NaCl$: Which is soluble in water* * According to table 3.1 (Page 101). Since we have an insoluble product, there will be precipitation. - This is a precipitation reaction. Since we already have the reactants and the products, the final chemical reaction is: $ZnCl_2(aq) + Na_2CO_3(aq) \lt -- \gt ZnCO_3(s) + 2NaCl(aq)$ - The reaction is balanced.