Chemistry: The Molecular Science (5th Edition)

Published by Cengage Learning
ISBN 10: 1285199049
ISBN 13: 978-1-28519-904-7

Chapter 2 - Chemical Compounds - Questions for Review and Thought - General Questions - Page 90e: 111c


$$5.261*10^{21} molecules$$

Work Step by Step

We solve to find: $$ \frac{.280 g}{1}* \frac{1 mol}{194.12 g}* \frac{8 mol \ C \ atoms}{mol} \frac{6.022*10^{23} molecules}{mol \ C \ atoms}=5.261*10^{21} molecules$$
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