Chemistry: The Molecular Science (5th Edition)

Published by Cengage Learning
ISBN 10: 1285199049
ISBN 13: 978-1-28519-904-7

Chapter 2 - Chemical Compounds - Questions for Review and Thought - General Questions - Page 90e: 111b

Answer

$$6.57*10^{20} molecules$$

Work Step by Step

We find: $$ \frac{.212 g}{1}* \frac{1 mol}{194.12 g}* \frac{6.022*10^{23} molecules}{mol}=\\6.57*10^{20} molecules$$
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