Answer
$_{84}^{212}Po → _{82}^{208}Pb + _{2}^{4}He$
Work Step by Step
Po-212 undergoes alpha emission to form Pb-208.
Chemistry: The Molecular Science (5th Edition)
by Moore, John W.; Stanitski, Conrad L.
Published by
Cengage Learning
ISBN 10:
1285199049
ISBN 13:
978-1-28519-904-7
Chapter 18 - Nuclear Chemistry - Questions for Review and Thought - Topical Questions - Page 817b: 21d
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