Chemistry: The Molecular Science (5th Edition)

Published by Cengage Learning
ISBN 10: 1285199049
ISBN 13: 978-1-28519-904-7

Chapter 18 - Nuclear Chemistry - Questions for Review and Thought - General Questions - Page 817d: 70b


$^{45}Ti\rightarrow \,^{45}Sc+\text{positron}$

Work Step by Step

a Positron is a positively charged electron. Positron emission leads to a unit decrease in the atomic number. Therefore, the missing product has an atomic number of one less than that of $Ti$. That is, Z= (Z of $Ti$)-1=22-1=21. The element with atomic number 21 is scandium ($Sc$). There is no change in mass number as the mass number of a positron is 0. Therefore, the missing product is $\,^{45}Sc$.
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