Chemistry: The Molecular Science (5th Edition)

Published by Cengage Learning
ISBN 10: 1285199049
ISBN 13: 978-1-28519-904-7

Chapter 18 - Nuclear Chemistry - Questions for Review and Thought - General Questions - Page 817d: 74a



Work Step by Step

Let the missing product be $\,^{A}_{Z}X$ where $X$ is the symbol, $Z$ is the atomic number and $A$ is the mass number. As the sum of masses on both sides must be equal: $238+14=A+(5\times1)\implies A=238+14-5=247$ As the sum of charges must be equal: $92+7=Z+(5\times0)$ or $Z=99$ The symbol of the element with atomic number 99 is $Es$. Therefore, the missing product is $\,^{247}_{99}Es$
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