Answer
$^{247}_{99}Es$
Work Step by Step
Let the missing product be $\,^{A}_{Z}X$ where $X$ is the symbol, $Z$ is the atomic number and $A$ is the mass number.
As the sum of masses on both sides must be equal:
$238+14=A+(5\times1)\implies A=238+14-5=247$
As the sum of charges must be equal:
$92+7=Z+(5\times0)$ or $Z=99$
The symbol of the element with atomic number 99 is $Es$.
Therefore, the missing product is $\,^{247}_{99}Es$
