Chemistry: The Molecular Science (5th Edition)

Published by Cengage Learning
ISBN 10: 1285199049
ISBN 13: 978-1-28519-904-7

Chapter 17 - Electrochemistry and Its Applications - Questions for Review and Thought - Topical Questions - Page 782c: 45



Work Step by Step

$\ln K°=\frac{nFE°_{cell}}{RT}=\frac{2\times(96485\,C/mol\,e^{-})\times-0.027\,V}{(8.314\,J/mol\,K)\times298K}$ $=-2.102942$ $K°=e^{-2.102942}=0.12$ As the reaction occurs in aqueous solution, $K°=K_{c}=0.12$
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