Answer
0.12
Work Step by Step
$\ln K°=\frac{nFE°_{cell}}{RT}=\frac{2\times(96485\,C/mol\,e^{-})\times-0.027\,V}{(8.314\,J/mol\,K)\times298K}$
$=-2.102942$
$K°=e^{-2.102942}=0.12$
As the reaction occurs in aqueous solution,
$K°=K_{c}=0.12$
Chemistry: The Molecular Science (5th Edition)
by Moore, John W.; Stanitski, Conrad L.
Published by
Cengage Learning
ISBN 10:
1285199049
ISBN 13:
978-1-28519-904-7
Chapter 17 - Electrochemistry and Its Applications - Questions for Review and Thought - Topical Questions - Page 782c: 45
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