Answer
0.360 V
Work Step by Step
The cell can be represented as
$Zn|Zn^{2+}||Cd^{2+}|Cd$
$E^{0}_{cell}= E^{0}_{right}-E^{0}_{left}=$
$-0.403\,V-(-0.763\,V)= 0.360\,V$
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