Chemistry: The Molecular Science (5th Edition)

Published by Cengage Learning
ISBN 10: 1285199049
ISBN 13: 978-1-28519-904-7

Chapter 14 - Acids and Bases - Problem Solving Practice 14.4 - Page 618: a

Answer

$pH = 12.60$

Work Step by Step

- $NaOH$ is a strong base, therefore: $[OH^-] = [NaOH] = 0.040M$ $pOH = -log[OH^-]$ $pOH = -log( 0.04)$ $pOH = 1.40$ $pH + pOH = 14$ $pH + 1.40 = 14$ $pH = 12.60$
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