## Chemistry: The Molecular Science (5th Edition)

$pH = 12.60$
- $NaOH$ is a strong base, therefore: $[OH^-] = [NaOH] = 0.040M$ $pOH = -log[OH^-]$ $pOH = -log( 0.04)$ $pOH = 1.40$ $pH + pOH = 14$ $pH + 1.40 = 14$ $pH = 12.60$