Chemistry: The Molecular Science (5th Edition)

Published by Cengage Learning
ISBN 10: 1285199049
ISBN 13: 978-1-28519-904-7

Chapter 14 - Acids and Bases - Exercise 14.3 - Acids and Bases - Page 609: d


$(CH_3)_2NH(aq) + H_2O(l) \lt -- \gt (CH_3)_2N{H_2}^+(aq) + OH^-(aq)$

Work Step by Step

$(CH_3)_2NH$ is a base, therefore, it will receive one proton from the other reactant, in this case, the water molecules. - When $(CH_3)_2NH$ receives one proton, it produces $(CH_3)_2N{H_2}^+$, and when $H_2O$ donates one proton, it will produce $OH^-$.
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