Chemistry: The Molecular Science (5th Edition)

Published by Cengage Learning
ISBN 10: 1285199049
ISBN 13: 978-1-28519-904-7

Chapter 14 - Acids and Bases - Exercise 14.3 - Acids and Bases - Page 609: c


$CH_3NH_2(aq) + H_2O(l) \lt -- \gt CH_3N{H_3}^+(aq) + OH^-(aq)$

Work Step by Step

$CH_3NH_2$ is a base, therefore, it will receive one proton from the other reactant, in this case, the water molecule. When $CH_3NH_2$ receives a proton, it produces $ CH_3N{H_3}^+$, and when $H_2O$ donates this proton, it will produce $OH^-$.
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