Chemistry: The Molecular Science (5th Edition)

Published by Cengage Learning
ISBN 10: 1285199049
ISBN 13: 978-1-28519-904-7

Chapter 12 - Chemical Equilibrium - Questions for Review and Thought - Topical Questions - Page 523b: 34


$2.6\times10^{-9} M$

Work Step by Step

$K_{c} = \frac{[Br_{2}][F_{2}]^{5}}{[BrF_{5}]^{2}} = \frac{(0.0018)(0.0090)^{5}}{(0.0064)^{2}} = 2.6\times10^{-9} M$
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