## Chemistry: The Molecular Science (5th Edition)

Published by Cengage Learning

# Chapter 12 - Chemical Equilibrium - Questions for Review and Thought - Topical Questions - Page 523b: 24c

#### Answer

We see that the upper reaction is the flipped version of the lower reaction, meaning that $K_{c1}$ is the inverse of $K_{c2}$. In addition, we see that the coefficients of the upper reaction are equal to exactly half of the coefficients of the lower reaction, meaning: $K_{c2}=\frac{1}{k_{c1}^2}$

#### Work Step by Step

We see that the upper reaction is the flipped version of the lower reaction, meaning that $K_{c1}$ is the inverse of $K_{c2}$. In addition, we see that the coefficients of the upper reaction are equal to exactly half of the coefficients of the lower reaction, meaning: $K_{c2}=\frac{1}{k_{c1}^2}$

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