Chemistry: Molecular Approach (4th Edition)

Published by Pearson
ISBN 10: 0134112830
ISBN 13: 978-0-13411-283-1

Chapter 9 - Exercises - Page 421: 65

Answer

$H_2CS$ is the better structure because the formal charge on $C$ and $S$ is zero in this structure.

Work Step by Step

We know, formal charge = no. of valence electrons - (no. of nonbonding electrons + 1/2 no. of shared electrons) In $H_2CS$, Formal charge on carbon = 4 - (0+ 1/2*8) = 0 Formal charge on sulfur = 6 - (4+ 1/2*4) = 0 In $H_2SC$, Formal charge on carbon = 4 - (4+ 1/2*4) = -2 Formal charge on sulfur = 6 - (0+ 1/2*8) = 2 $H_2CS$ is the better structure because the formal charge on $C$ and $S$ is zero in this structure.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.