# Chapter 9 - Exercises - Page 421: 55

The bonds will be : a. pure covalent b. polar covalent c. pure covalent d. ionic bond

#### Work Step by Step

a. The bond is formed by sharing of electrons between the two $Br$ atoms, so it is covalent. There is no electronegativity difference, so the bond is pure covalent. b. The bond is formed by sharing of electrons between the $C$ and $Cl$ atoms, so it is covalent. There is electronegativity difference between the two atoms (Cl is more electronegative), so the bond is polar covalent. c. The bond is formed by sharing of electrons between the $C$ and $S$ atoms, so it is covalent. There is negligible electronegativity difference between the two atoms, so the bond is pure covalent. d. The bond is formed between the $O^{2-}$ and $Sr^+$ ions, so it is ionic.

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.