Answer
$6.46\times10^{4}\,kJ$
Work Step by Step
Heat= $5.56\times10^{3}\,g\,CH_{3}NO_{2}\times\frac{1\,mol\,CH_{3}NO_{2}}{61.04\,g\,CH_{3}NO_{2}}\times\frac{-1418\,kJ}{2\,mol\,CH_{3}NO_{2}}$
$=-6.46\times10^{4}\,kJ$
The negative sign indicates that the heat is liberated and can be neglected.
Heat produced= $6.46\times10^{4}\,kJ$
