Answer
5.34 g
Work Step by Step
Mass of $CH_{4}$ that must burn=
$267\,kJ\times\frac{1\,mol\,CH_{4}}{802.3\,kJ}\times\frac{16.04\,g\,CH_{4}}{1\,mol\,CH_{4}}$
$=5.34\,g\,CH_{4}$
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