Chemistry: Molecular Approach (4th Edition)

Published by Pearson
ISBN 10: 0134112830
ISBN 13: 978-0-13411-283-1

Chapter 5 - Section 5.4 - The Ideal Gas Law - For Practice - Page 211: 5.6

Answer

Volume = 16.07 L

Work Step by Step

0.556 mol of gas occupy at a pressure of 715 mmHg and a temperature of 58 °C V = ?, n = 0.556, $T =58 ^{\circ} C$, P = 715 mmHg T = 58 + 273.15 = 331.15 K P = 715 mmHg / 760 = 0.94 atm using PV = nRT (where R = 0.08206) V = 0.556 x 0.08206 x 331.15 / 0.94 = 16.07 L P = 0.552 x 0.08206 x 305 / 8.50 = 1.63 atm 1atm = 14.7 psi 1.63 atm = 14.7 x 1.63 psi = 23.9 psi
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