Chemistry: Molecular Approach (4th Edition)

Published by Pearson
ISBN 10: 0134112830
ISBN 13: 978-0-13411-283-1

Chapter 5 - Section 5.4 - The Ideal Gas Law - For Practice - Page 210: 5.5

Answer

P = 1.63 atm or 23.9 psi

Work Step by Step

An 8.50-L tire contains 0.552 mol of gas at a temperature of 305 K. What is the pressure V = 8.5, n = 0.552, T = 305, P = ? using PV = nRT (where R = 0.08206) P = 0.552 x 0.08206 x 305 / 8.50 = 1.63 atm 1atm = 14.7 psi 1.63 atm = 14.7 x 1.63 psi = 23.9 psi
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