Chemistry: Molecular Approach (4th Edition)

Published by Pearson
ISBN 10: 0134112830
ISBN 13: 978-0-13411-283-1

Chapter 3 - Exercises - Page 132: 75


The mass of fluorine in 55.5 g of this compound is equal to 20.8 g.

Work Step by Step

Use the percent composition of mass as a conversion factor to find the mass of fluorine. $100\%$ copper(II) fluoride = $37.42\%$ fluorine. $55.5 g$ copper (II) fluoride $\times \frac{37.42\%-fluorine}{100\%-copper(II)-fluoride} = 20.8$ g $fluorine$.
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