## Chemistry: Molecular Approach (4th Edition)

$NH_3$: $82.27\%$ $CO(NH_2)_2: 46.65\%$ $NH_4NO_3: 35.00\%$ $(NH_4)_2SO_4: 21.20\%$ The compound with highest nitrogen content is $NH_3$, with $82.28\%$
$NH_3:$ 1. Calculate the molar mass of: $NH_3$ Molar Mass ($NH_3$): 14.01* 1 + 1.008* 3 = 17.03g/mol 2. Calculate the total mass of $N$ in one mole of this compound: Total Mass ($N$): $1 \times 14.01g = 14.01g$ 3. Find the mass percent composition: $\frac{Total-mass (N)}{Molar-Mass} \times 100\% = \frac{ 14.01}{ 17.03} \times 100\% = 82.27\%$ $CO(NH_2)_2$$:$ 1. Calculate the molar mass of: $CO(NH_2)_2$ Molar Mass ($CO(NH_2)_2$): 12.01* 1 + 16* 1 + 2 * ( 14.01* 1 + 1.008* 2) = 60.06g/mol 2. Calculate the total mass of $N$ in one mole of this compound: Total Mass ($N$): $2 \times 14.01g = 28.02g$ 3. Find the mass percent composition: $\frac{Total-mass (N)}{Molar-Mass} \times 100\% = \frac{ 28.02}{ 60.06} \times 100\% = 46.65\%$ $NH_4NO_3:$ 1. Calculate the molar mass of: $NH_4NO_3$ Molar Mass ($NH_4NO_3$): 14.01* 1 + 1.008* 4 + 14.01* 1 + 16* 3 ) = 80.05g/mol 2. Calculate the total mass of $N$ in one mole of this compound: Total Mass ($N$): $2 \times 14.01g = 28.02g$ 3. Find the mass percent composition: $\frac{Total-mass (N)}{Molar-Mass} \times 100\% = \frac{ 28.02}{ 80.05} \times 100\% = 35.00\%$ $(NH_4)_2SO_4$: 1. Calculate the molar mass of: $(NH_4)_2SO_4$ Molar Mass ($(NH_4)_2SO_4$): 2 * ( 14.01* 1 + 1.008* 4 ) + 32.07* 1 + 16.00* 4 = 132.2g/mol 2. Calculate the total mass of $N$ in one mole of this compound: Total Mass ($N$): $2 \times 14.01g = 28.02g$ 3. Find the mass percent composition: $\frac{Total-mass (N)}{Molar-Mass} \times 100\% = \frac{ 28.02}{ 132.2} \times 100\% = 21.20\%$ ------ Therefore, the compound with highest nitrogen content is $NH_3$, with $82.28\%$