Chemistry: Molecular Approach (4th Edition)

Published by Pearson
ISBN 10: 0134112830
ISBN 13: 978-0-13411-283-1

Chapter 25 - Exercises - Page 1154: 34

Answer

(a) \[{{\left[ Co{{\left( {{H}_{2}}O \right)}_{2}}{{\left( ox \right)}_{2}} \right]}^{-}}\] will exhibit geometrical isomerism. (b) \[{{\left[ Cr{{\left( en \right)}_{3}} \right]}^{3+}}\] will exhibit geometrical isomerism. (c) \[{{\left[ Co{{\left( {{H}_{2}}O \right)}_{2}}{{\left( N{{H}_{3}} \right)}_{2}}\left( ox \right) \right]}^{+}}\] will exhibit geometrical isomerism. (d) \[{{\left[ Ni{{\left( N{{H}_{3}} \right)}_{2}}\left( en \right) \right]}^{2+}}\] will not exhibit geometrical isomerism. (e) \[\left[ Ni{{\left( CO \right)}_{2}}C{{l}_{2}} \right]\] will exhibit geometrical isomerism.

Work Step by Step

Geometrical isomerism is a type of stereoisomerism that results when the ligands bonded to the metal have a different spatial arrangement. Geometrical isomerism (cis–trans isomerism) occurs in the square planar complexes of the type \[M{{A}_{2}}{{B}_{2}}\] and octahedral complexes of the \[M{{A}_{4}}{{B}_{2}}.\]Geometrical isomerism does not occur in tetrahedral complexes because all the bond angles around the central metal are \[109.5{}^\circ \] and each comer of a tetrahedron can be considered to be adjacent to all other corners. Similarly, a linear complex cannot exhibit cis–trans isomerism.
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