# Chapter 25 - Exercises - Page 1154: 33

(a) ${{\left[ Cr{{\left( N{{H}_{3}} \right)}_{5}}\left( OH \right) \right]}^{2+}}$ will not exhibit geometrical isomerism. (b) ${{\left[ Cr{{\left( en \right)}_{2}}C{{l}_{2}} \right]}^{+}}$ will exhibit geometrical isomerism. (c) ${{\left[ Cr\left( {{H}_{2}}O \right){{\left( N{{H}_{3}} \right)}_{3}}C{{l}_{2}} \right]}^{+}}$ will exhibit geometrical isomerism. (d) ${{\left[ Pt\left( N{{H}_{3}} \right)C{{l}_{3}} \right]}^{-}}$ will not exhibit geometrical isomerism. (e) $\left[ Pt{{\left( {{H}_{2}}O \right)}_{2}}{{\left( CN \right)}_{2}} \right]$ will exhibit geometrical isomerism.

#### Work Step by Step

Geometrical isomerism is a type of stereoisomerism that results when the ligands bonded to the metal have a different spatial arrangement. Geometrical isomerism (cis–trans isomerism) occurs in the square planar complexes of the type $~M{{A}_{2}}{{B}_{2}}$ and octahedral complexes of the type $M{{A}_{4}}{{B}_{2}}$. Geometrical isomerism does not occur in tetrahedral complexes because all the bond angles around the central metal and each corner of a tetrahedron can be considered to be adjacent to all other corners. Similarly, a linear complex cannot exhibit cis–trans isomerism.

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