Answer
a. hexaaquachromium (III)
b. tetracyanocuprate (II)
c. pentaaminebromoiron (III) sulfate
d. amminetetraaquanhydroxycobalt (III) chloride
Work Step by Step
a. According to IUPAC, a cationic coordination compound is named by naming the ligand first followed by the metal cation. The oxidation state of the cation is stated in Roman numerals in parenthesis. When water is the ligand in the complex, it is named as aqua. Thus, the name of the complex \[{{\left( Cr{{\left( {{H}_{2}}O \right)}_{6}} \right)}^{3+}}\] is hexaaquachromium (III).
b. According to IUPAC, an anionic coordination compound is named by naming the ligand first followed by the metal cation with the suffix -ate. The oxidation state of the cation is stated in parenthesis in Roman numerals. Thus, the name of the complex \[{{\left( Cu{{\left( CN \right)}_{4}} \right)}^{2-}}\] is tetracyanocuprate (II).
c. According to IUPAC, a cationic coordination compound is named by naming the ligand first followed by the metal cation. The oxidation state of the cation is stated in Roman numerals in parenthesis. When there is more than one ligand present in the complex, the ligands are named in the alphabetical order. Thus, the name of the complex \[\left[ Fe{{\left( N{{H}_{3}} \right)}_{5}}Br \right]S{{O}_{4}}\] is pentaaminebromoiron (III) sulfate.
d. According to IUPAC, a cationic coordination compound is named by naming the ligand first followed by the metal cation. The oxidation state of cation is stated in Roman numerals in parenthesis. When there is more than one ligand present in the complex, the ligands are named in the alphabetical order. Thus, the name of the complex\[\left[ Co{{\left( {{H}_{2}}O \right)}_{4}}\left( N{{H}_{3}} \right)\left( OH \right) \right]C{{l}_{2}}\] is amminetetraaquanhydroxycobalt (III) chloride.
