Chemistry: Molecular Approach (4th Edition)

Published by Pearson
ISBN 10: 0134112830
ISBN 13: 978-0-13411-283-1

Chapter 2 - Exercises: 121


106.91 amu

Work Step by Step

Then the mass of Ag-109 is 1.0187z. 100% - 51.839% = 48.161% Ag-109 0.51839z + 0.48161(1.0187z) = 107.87 Solve for z algebraically: z = 106.91 amu
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.