Chemistry: Molecular Approach (4th Edition)

Published by Pearson
ISBN 10: 0134112830
ISBN 13: 978-0-13411-283-1

Chapter 2 - Exercises: 119

Answer

75% Au

Work Step by Step

One mole of atoms contains 6.022x10^23 atoms. 2.49 x 10^23 / 6.022x10^23 = 0.4135 mole of atoms. 1 mole of gold = 197.0 g 1 mole of palladium = 106.4 g mole Au + mole Pd = 0.4135 mole Au x 197 + mole Pd x 106.4 = 67.2 Two equations in two unknowns mole Au = 0.2561 mole Pd = 0.1574 grams Au = 0.2561 x 197 = 50.45 g 50.45 / 67.2 = 0.75 (75% Au)
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