Chemistry: Atoms First (2nd Edition)

Published by Cengage Learning
ISBN 10: 1305079248
ISBN 13: 978-1-30507-924-3

Chapter 3 - Integrative Problems - Page 150j: 158

Answer

See the explanation

Work Step by Step

a. $Fe^{2+}$: - Total number of protons: 26 (iron has 26 protons) - Total number of electrons: 24 (since it is a positive ion, it has lost 2 electrons) - The simplest compound formed between $Fe^{2+}$ and the oxide ion ($O^{2-}$) is iron(II) oxide, with the formula $FeO$. b. $Fe^{3+}$: - Total number of protons: 26 (iron has 26 protons) - Total number of electrons: 23 (since it is a positive ion, it has lost 3 electrons) - The simplest compound formed between $Fe^{3+}$ and the oxide ion ($O^{2-}$) is iron(III) oxide, with the formula $Fe_2O_3$. c. $Ba^{2+}$: - Total number of protons: 56 (barium has 56 protons) - Total number of electrons: 54 (since it is a positive ion, it has lost 2 electrons) - The simplest compound formed between $Ba^{2+}$ and the oxide ion ($O^{2-}$) is barium oxide, with the formula $BaO$. d. $Cs^{+}$: - Total number of protons: 55 (cesium has 55 protons) - Total number of electrons: 54 (since it is a positive ion, it has lost 1 electron) - The simplest compound formed between $Cs^{+}$ and the oxide ion ($O^{2-}$) is cesium oxide, with the formula $Cs_2O$. e. $S^{2-}$: - Total number of protons: 16 (sulfur has 16 protons) - Total number of electrons: 18 (since it is a negative ion, it has gained 2 electrons) - The simplest compound formed between $S^{2-}$ and the aluminum ion ($Al^{3+}$) is aluminum sulfide, with the formula $Al_2S_3$. f. $P^{3-}$: - Total number of protons: 15 (phosphorus has 15 protons) - Total number of electrons: 18 (since it is a negative ion, it has gained 3 electrons) - The simplest compound formed between $P^{3-}$ and the aluminum ion ($Al^{3+}$) is aluminum phosphide, with the formula $AlP$. g. $Br^{-}$: - Total number of protons: 35 (bromine has 35 protons) - Total number of electrons: 36 (since it is a negative ion, it has gained 1 electron) - The simplest compound formed between $Br^{-}$ and the aluminum ion ($Al^{3+}$) is aluminum bromide, with the formula $AlBr_3$. h. $N^{3-}$: - Total number of protons: 7 (nitrogen has 7 protons) - Total number of electrons: 10 (since it is a negative ion, it has gained 3 electrons) - The simplest compound formed between $N^{3-}$ and the aluminum ion ($Al^{3+}$) is aluminum nitride, with the formula $AlN$.
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