Answer
a. B$_{2}$O$_{3}$
b. AsF$_{5}$
c. N$_{2}$O
d. SCl$_{6}$
Work Step by Step
a. In this compound, according to the prefixes, we have two atoms of boron (B) and three atoms of oxygen (O). The formula for this compound is B$_{2}$O$_{3}$.
b. In this compound, according to the prefixes, we have one atom of arsenic (As) and five atoms of fluorine (F). We know there is just one atom of arsenic because the first element in the compound doesn't take on a prefix if there is only one atom of that element in the compound. The formula for this compound is AsF$_{5}$.
c. In this compound, according to the prefixes, we have two atoms of nitrogen (N) and one atom of oxygen (O). The formula for this compound is N$_{2}$O.
d. In this compound, according to the prefixes, we have one atom of sulfur (S) and six atoms of chlorine (Cl). We know there is just one atom of sulfur because the first element in the compound doesn't take on a prefix if there is only one atom of that element in the compound. The formula for this compound is SCl$_{6}$.
