Answer
a. \( 2\mathrm{Cs}(s)+2\mathrm{H}_{2} \mathrm{O}(l) \rightarrow 2\mathrm{CsOH}(aq)+\mathrm{H}_{2}(g) \)
b. \( 2\mathrm{Na}(\mathrm{s})+\mathrm{Cl}_{2}(\mathrm{~g}) \rightarrow 2\mathrm{NaCl}(\mathrm{s}) \)
Work Step by Step
Let's explain the balanced equations:
a. \( 2\mathrm{Cs}(s)+2\mathrm{H}_{2} \mathrm{O}(l) \rightarrow 2\mathrm{CsOH}(aq)+\mathrm{H}_{2}(g) \)
In this reaction, 2 atoms of cesium (\( \mathrm{Cs} \)) react with 2 molecules of water (\( \mathrm{H}_{2} \mathrm{O} \)) to form 2 molecules of cesium hydroxide (\( \mathrm{CsOH} \)) in aqueous solution and 1 molecule of hydrogen gas (\( \mathrm{H}_{2} \)).
b. \( 2\mathrm{Na}(\mathrm{s})+\mathrm{Cl}_{2}(\mathrm{~g}) \rightarrow 2\mathrm{NaCl}(\mathrm{s}) \)
In this reaction, 2 atoms of sodium (\( \mathrm{Na} \)) react with 1 molecule of chlorine gas (\( \mathrm{Cl}_{2} \)) to form 2 molecules of sodium chloride (\( \mathrm{NaCl} \)).
Balancing chemical equations is important because it reflects the law of conservation of mass, which states that matter cannot be created or destroyed in a chemical reaction.
