Chemistry: Atoms First (2nd Edition)

Published by Cengage Learning
ISBN 10: 1305079248
ISBN 13: 978-1-30507-924-3

Chapter 2 - Exercises - Page 99b: 43

Answer

$9.4\times 10^{14}s^{-1}$ to $1.1 \times 10^{15}s^{-1}$

Work Step by Step

We us the formula $f =\frac{c}{λ},$ where $c$ is the speed of light and $\lambda$ is the wavelength ($280-320$ nm for UV B light). $f_1=\frac{3\times 10^8}{280\times 10^{-9}}\approx 1.1\times 10^{15}s^{-1}$ $f_2=\frac{3\times 10^8}{320\times 10^{-9}}\approx 9.4\times 10^{14}s^{-1}$ The frequency range of light that octyl methoxycinnamate and oxybenzone compounds (common in sunscreen) absorb is from $9.4\times 10^{14}s^{-1}$ to $1.1 \times 10^{15}s^{-1}$.
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