Chemistry: Atoms First (2nd Edition)

Published by Cengage Learning
ISBN 10: 1305079248
ISBN 13: 978-1-30507-924-3

Chapter 13 - Exercises - Page 575c: 59

Answer

$[HI] = 3.162 \times 10^{- 3}M$

Work Step by Step

1. Calculate the hydronium concentration: $[H_3O^+] = 10^{-pH}$ $[H_3O^+] = 10^{- 2.5}$ $[H_3O^+] = 3.162 \times 10^{- 3}M$ 2. Since $HI$ is a strong acid: $[HI] = [H_3O^+] = 3.162 \times 10^{- 3}M$
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