Answer
$[OH^-] = 1.259\times 10^{- 12}M$
$[H_3O^+] = 7.943\times 10^{- 3}M$
pOH = 11.9
- Gastric juice is acidic.
Work Step by Step
1. Calculate the hydronium concentration:
$[H_3O^+] = 10^{-pH}$
$[H_3O^+] = 10^{- 2.1}$
$[H_3O^+] = 7.943 \times 10^{- 3}$
2. Calculate the pOH, then the hydroxide ion concentration:
pH + pOH = 14
2.1 + pOH = 14
pOH = 11.9
$[OH^-] = 10^{-pOH}$
$[OH^-] = 10^{- 11.9}$
$[OH^-] = 1.259 \times 10^{- 12}$
- Since $[H_3O^+] > [OH^-]$, the solution is acidic.
