Chemistry: Atoms First (2nd Edition)

Published by Cengage Learning
ISBN 10: 1305079248
ISBN 13: 978-1-30507-924-3

Chapter 12 - Exercises - Page 524c: 29

Answer

$$K_P = 6.3 \times 10^{-13}$$

Work Step by Step

- The exponent of each pressure is equal to its balance coefficient. $$K_P = \frac{P_{Products}}{P_{Reactants}} = \frac{P_{ NO } ^{ 2 }P_{ O_2 }}{P_{ NO_2 } ^{ 2 }}$$ 2. Substitute the values and calculate the constant value: $$K_P = \frac{( 6.5 \times 10^{-5} )^{ 2 }( 4.5 \times 10^{-5} )}{( 0.55 )^{ 2 }} = 6.3 \times 10^{-13}$$
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