## Chemistry and Chemical Reactivity (9th Edition)

a) None of them are making a $\pi$ bond so they are all $sp^3$ hybridized. b) The two atoms involved in the double bond make a $\pi$ bond so they are $sp^2$ hybridized. The other is $sp^3$ hybridized. c) The carbon atom involved in the double bond makes a $\pi$ bond so it is $sp^2$ hybridized. The other two atoms are $sp^3$ hybridized.