Chapter 9 Bonding and Molecular Structure: Orbital Hybridization and Molecular Orbitals - Study Questions - Page 369a: 19

See the answer below.

$H_2^+$ has one valence electron so the configuration is: $(\sigma_{1s})^1$ Since $B.O.=(N.\ Bonding -N.\ Antibonding)/2$ This ion has a bond order if 0.5 thus having a weaker bond than $H_2$ with a bond order of 1.