Answer
See the answer below.
Work Step by Step
Volume of water:
$2.54\ cm\div 100\ cm/m\times 2.59\times 10^6\ m^2= 6.58\times10^4\ m^3$
Density: $1\ g/cm^3=1000\ kg/m^3$
Number of moles:
$6.58\times10^4\ m^3\times1000\ kg/m^3\times1000\ g/kg\div 18.015\ g/mol=3.65\times10^9\ mol$
Heat released on condensation:
$3.65\times10^9\ mol\times 44.0\ kJ/mol=1.61\ times 10^{11}\ kJ$
Or
$1.61\ times 10^{11}\ kJ\div4.2\times10^6\ kJ/ton=38257\ ton\ TNT$
