Answer
See the answer below.
Work Step by Step
a) $Br_2(l)\rightarrow Br_2(g)$
$30.9-0=30.9\ kJ/mol$
b) $Br_2(g)\rightarrow 2\ Br(g)$
$2\times111.9-30.9=192.9\ kJ/mol$
Chemistry and Chemical Reactivity (9th Edition)
by Kotz, John C.; Treichel, Paul M.; Townsend, John R.; Treichel, David A.
Published by
Cengage Learning
ISBN 10:
1133949649
ISBN 13:
978-1-13394-964-0
Chapter 5 Principles of Chemical Reactivity: Energy and Chemical Reactions - Study Questions - Page 217i: 112
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